Lab 2 Hacks

//Hack #1: Create method that sets all elements in array to n
void setArray(int[] arr, int n) {
    for (int i = 0; i < arr.length; i++) {
        arr[i] = n;
        //sets each of the 0 to n, which is 10 in this case
    }
}

int[] array = new int[10];
setArray(array, 10);

for (int i = 0; i<array.length; i++) {
    System.out.println(array[i]);
}

// Should print all 10s when working properly
10

10
10
10
10
10
10
10
10
10
10

10

//Hack #2: Write an array to find the average of an array
//Example finding the max in an array. 

//Finds the maximum in an array
public static int average(int[] array) {
    int sum = 0;
    for (int i = 0; i < array.length; i++) {
        sum += array[i];
    } //adds each array element to sum and divides by length of array
    return sum / array.length;
}

//tester array
int[] test = {3, 5, 7, 2, 10};

//returns 10
System.out.println(average(test));

5

public static void main(String[] args){
    int[][] arrayOne = new int[5][7];
    for (int row = 0; row < arrayOne.length; row++){
        for (int col = 0; col < arrayOne[row].length; col++){
            arrayOne[row][col] = row+col - 1;
        }
    }

    System.out.println(arrayOne[4][6]);
}

//Hack 3 - print average of diagonal
public static double averageDiagonal (int[][] array2D) {
    // your code here
    int sum = 0;
    int count = 0;
    int row = 0;
    int col = 0;
    
    // Iterate over the diagonal elements of the array
    while (row < array2D.length && col < array2D[0].length) {
        sum += array2D[row][col];
        count++;
        row++;
        col++;
    }
    
    // Calculate and return the average as double
    return (double) sum / count;
}

int[][] arr = {
    {1,2,3,4},
    {5,6,7,8},
    {9,1,2,3}
    //populating an arr
};

System.out.println(averageDiagonal(arr));

3.0